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Tuesday 25 December 2012

P.No. 4.6:- 100meter cube of water is pumped from a reservoir into a tank, 10m higher than the reservoir, in 20 minutes. Find (a) The increase in P.E (b) The power delivered by the pump.


P.No.   4.6:- 100m³ of water is pumped from a reservoir into a tank, 10m higher than the reservoir, in 20 minutes. Find

       (a)  The increase in P.E

       (b)  The power delivered by the pump.

Solution:-

Given data:-

                 Volume of water   = V =     100m³

                  Height                  = h =      10m

                   Time taken          = t =      20min   =   20 × 60s   = 1200s

To determine:-

                          Potential energy =   P.E =?

                           Power                 =   P    =?

Calculation:-

 ( we know that work done is equal to change in energy it may be kinetic or potential but  in this case only P.E is involved. So,)

                 Work done = Increase in P.E     

                                    = mgh

                To determine mass ‘m’ we first take

                     Density = mass/volume

   Or,                 ρ = m/V



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