Problem No.4.3:-
Ten bricks, each 6.0 cm thick mass 1.5kg, lie flat on a table. How much
work is required to stack them one on the top of another?
Solution:-
Given Data:-
To Determine:-
Work done by
placing them one on the top of another = W =?
Calculation:-
Now first of all
suppose that all bricks are on the ground. Now you lift a brick i.e.; 2nd
and placed it on any one of them which is 1st, now they are two
bricks, after that you lift a third one and placed it on the other two, and so
on.
Now think for a while that when you lift 2nd
brick and placed it 1st brick then 1st brick remain on
its place and you never do any work to lift it.
So, we conclude that we work done only on 9 bricks and not
on the 10th which is basically the 1st brick.
Hence,
Total weight
of 9 bricks = w = mg
After that when you
manage the all of these bricks then, their height is 60cm but their combined
center of gravity is 30cm.
How center of gravity is affecting and reducing it's length to half..?
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